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Farah Fatin Lyssa
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  • ▼  2012 (15)
    • ▼  June (15)
      • DAY 6 (19/06/2012)
      • Extra Notes
      • Properties of the Complex Set
      • Complex Numbers
      • DAY 5 (15/06/2012)
      • DAY 4 (14/06/2012)
      • DAY 3 (13/06/2012)
      • DAY 2 (12/06/2012)
      • DAY 1 (11/06/2012)
      • Rules of Integration
      • Practice make perfect!!!!!
      • Games of Gradients
      • Awesome video to calculate gradient
      • Gradient (Slope) of a Straight Line
      • Salam Perkenalan

List of Topics

  • Complex Numbers (3)
  • Gradient (4)
  • Integration (1)
  • Reflection (6)

Blog Archive

  • ▼  2012 (15)
    • ▼  June (15)
      • Salam Perkenalan
      • Gradient (Slope) of a Straight Line
      • Awesome video to calculate gradient
      • Games of Gradients
      • Practice make perfect!!!!!
      • Rules of Integration
      • DAY 1 (11/06/2012)
      • DAY 2 (12/06/2012)
      • DAY 3 (13/06/2012)
      • DAY 4 (14/06/2012)
      • DAY 5 (15/06/2012)
      • Complex Numbers
      • Properties of the Complex Set
      • Extra Notes
      • DAY 6 (19/06/2012)

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Topic of Discussion

  • Complex Numbers (3)
  • Gradient (4)
  • Integration (1)
  • Reflection (6)
Sunday, 17 June 2012
In: Integration

Rules of Integration

Our proofs will involve searching for a function F(x) whose derivative is .
The integral of a differential of a function is the function plus a constant.
PROOF: If
then
and
EXAMPLE. Evaluate the integral
SOLUTION: By Rule 1, we have
A constant may be moved across the integral sign. NOTE: A variable may NOT be moved across the integral sign.
PROOF: If
then
and
EXAMPLE: Evaluate the integral
SOLUTION: By Rule 2,
and by Rule 1,
therefore,
The integral of du may be obtained by adding 1 to the ex­ponent and then dividing by this new exponent. NOTE: If n is minus 1, this rule is not valid and another method must be used.
PROOF.- If
then
EXAMPLE: Evaluate the integral
SOLUTION: By Rule 3,
EXAMPLE: Evaluate the integral
SOLUTION: First write the integral
as
Then, by Rule 2,
and by Rule 3,
The integral of a sum is equal to the sum of the integrals.
PROOF: If
then
such that
where
EXAMPLE: Evaluate the integral
SOLUTION: We will not combine 2x and -5x.
where C is the sum of .
EXAMPLE: Evaluate the integral
SOLUTION:
Now we will discuss the evaluation of the constant of integration.
If we are to find the equation of a curve whose first derivative is 2 times the independent variable x, we may write
or
We may obtain the desired equation for the curve by integrating the expression for dy; that is, by integrating both sides of equa­tion (1). If
then,
But, since
and
then
We have obtained only a general equation of the curve because a different curve results for each value we assign to C. This is shown in figure 6-7. If we specify that
x=0
And
y=6
we may obtain a specific value for C and hence a par­ticular curve.
Suppose that
then,
or
C=6
Figure 6-7.-Family of curves.
By substituting the value 6 into the general equation, we find that the equation for the particular curve is
which is curve C of figure 6-7.
The values for x and y will determine the value for C and also determine the particular curve of the family of curves.
In figure 6-7, curve A has a constant equal to - 4, curve B has a constant equal to 0, and curve C has a constant equal to 6.
EXAMPLE: Find the equation of the curve if its first derivative is 6 times the independent variable, y equals 2, and x equals 0.
SOLUTION. We may write
or
such that,
Solving for C when
x=0
and
y=2
We have
or
C=2
so that the equation of the curve is
 

Check out more notes here
http://people.hofstra.edu/stefan_waner/realworld/tutorials4/frames6_1.html
Posted by Farah Fatin Lyssa at 07:57
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